Mathematics · 2015
JEE Main · 10 April 2015, Shift 1 · Q77
If y(x) is the solution of the differential equation (x+2) (d y)/(d x)=x^2+4 x-9, x ≠-2 and y(0)=0, then y(-4) is equal to:
If $\displaystyle y(x)$ is the solution of the differential equation $\displaystyle (x+2) \frac{\mathrm{d} y}{\mathrm{~d} x}=x^2+4 x-9, x \neq-2$ and $\displaystyle y(0)=0$, then $\displaystyle y(-4)$ is equal to :
Official answer
(1)
$\displaystyle 0$
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JEE Main 2015 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.