Mathematics · 2020
JEE Main · 7 January 2020, Shift 2 · Q52
If (3+i sin θ)/(4-i cos θ), θ ∈[0,2 π], is a real number, then an argument of sin θ+i cos θ is:
If $\displaystyle \frac{3+i \sin \theta}{4-i \cos \theta}, \theta \in[0,2 \pi]$, is a real number, then an argument of $\displaystyle \sin \theta+i \cos \theta$ is :
Official answer
(1)
$\displaystyle \pi-\tan ^{-1}\left(\frac{4}{3}\right)$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.