Mathematics · 2014
JEE Main · 11 April 2014, Shift 1 · Q76
If for n ≥ 1, P_n =∫_1^e ( log x)^n d x, then P_10-90 P_8 is equal to:
If for $\displaystyle \mathrm{n} \geqslant 1, \mathrm{P}_{\mathrm{n}}=\int_1^{\mathrm{e}}(\log x)^{\mathrm{n}} \mathrm{d} x$, then $\displaystyle \mathrm{P}_{10}-90 \mathrm{P}_8$ is equal to :
Official answer
(3)
9e
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JEE Main 2014 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.