Mathematics · 2017
JEE Main · 9 April 2017, Shift 1 · Q75
If ∫_1^2 (d x)/((x^2-2 x+4)^(3/2))=k/(k +5), then k is equal to:
If $\displaystyle \int_1^2 \frac{\mathrm{~d} x}{\left(x^2-2 x+4\right)^{\frac{3}{2}}}=\frac{\mathrm{k}}{\mathrm{k}+5}$, then k is equal to :
Official answer
(1)
$\displaystyle 1$
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JEE Main 2017 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.