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Mathematics · 2024

JEE Main · 31 January 2024, Shift 1 · Q1

If f(x)=(4 x+3)/(6 x-4), x ≠ 2/3 and (f ° f)(x)=g(x), where g: R -{2/3} → R -{2/3}, then (gogog) (4) is equal to

If $\displaystyle f(x)=\frac{4 x+3}{6 x-4}, x \neq \frac{2}{3}$ and $\displaystyle (f \circ f)(x)=g(x)$, where $\displaystyle g: \mathbb{R}-\left\{\frac{2}{3}\right\} \rightarrow \mathbb{R}-\left\{\frac{2}{3}\right\}$, then (gogog) ($\displaystyle 4$) is equal to
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.