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Mathematics · 2021

JEE Main · 4 August 2021, Shift 2 · Q88

If (d w(t))/(d t)=t √(121-t^2) and w(0)=0, then the value of 3 w(√ 21 ) is \ \ \ \.

If $\displaystyle \frac{d w(t)}{d t}=t \sqrt{121-t^2}$ and $\displaystyle w(0)=0$, then the value of $\displaystyle 3 w(\sqrt{21})$ is \_\_\_\_.
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.