Mathematics · 2016
JEE Main · 10 April 2016, Shift 1 · Q88
If A >0, B >0 and A + B =(π)/6, then the minimum value of tan A + tan B is:
If $\displaystyle \mathrm{A}>0, \mathrm{~B}>0$ and $\displaystyle \mathrm{A}+\mathrm{B}=\frac{\pi}{6}$, then the minimum value of $\displaystyle \tan \mathrm{A}+\tan \mathrm{B}$ is :
Official answer
(3)
$\displaystyle 4-2 \sqrt{3}$
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JEE Main 2016 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.