Mathematics · 2022
JEE Main · 26 July 2022, Shift 1 · Q11
If (d y)/(d x)+2 y tan x= sin x, 0<x<(π)/2 and y((π)/3)=0, then the maximum value of y(x) is:
If $\displaystyle \frac{\mathrm{d} y}{\mathrm{~d} x}+2 y \tan x=\sin x, 0<x<\frac{\pi}{2}$ and $\displaystyle y\left(\frac{\pi}{3}\right)=0$, then the maximum value of $\displaystyle y(x)$ is :
Official answer
(1)
$\displaystyle \frac{1}{8}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.