Mathematics · 2021
JEE Main · 27 August 2021, Shift 1 · Q84
If y^1 / 4+y^-1 / 4=2 x, and (x^2-1) (d^2 y)/(d x^2)+α x (d y)/(d x)+β y=0, then |α-β| is equal to \ \ \ \.
If $\displaystyle y^{1 / 4}+y^{-1 / 4}=2 x$, and $\displaystyle \left(x^2-1\right) \frac{\mathrm{d}^2 y}{d x^2}+\alpha x \frac{\mathrm{~d} y}{\mathrm{~d} x}+\beta y=0$, then $\displaystyle |\alpha-\beta|$ is equal to \_\_\_\_.
Official answer
17
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.