Mathematics · 2020
JEE Main · 8 January 2020, Shift 2 · Q75
If (√ 2 sin α)/(√(1+ cos 2 α))=1/7 and √((1- cos 2 β)/2)=1/(√ 10), α, β ∈(0, (π)/2), then tan (α+2 β) is equal to \ \ \ \.
If $\displaystyle \frac{\sqrt{2} \sin \alpha}{\sqrt{1+\cos 2 \alpha}}=\frac{1}{7}$ and $\displaystyle \sqrt{\frac{1-\cos 2 \beta}{2}}=\frac{1}{\sqrt{10}}$,
$\displaystyle \alpha, \beta \in\left(0, \frac{\pi}{2}\right)$, then $\displaystyle \tan (\alpha+2 \beta)$ is equal to
\_\_\_\_.
Official answer
1
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.