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Mathematics · 2024

JEE Main · 31 January 2024, Shift 2 · Q20

If a= sin^-1( sin (5)) and b= cos^-1( cos (5)), then a^2+b^2 is equal to

If $\displaystyle a=\sin ^{-1}(\sin (5))$ and $\displaystyle b=\cos ^{-1}(\cos (5))$, then $\displaystyle a^2+b^2$ is equal to
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.