Mathematics · 2018
JEE Main · 16 April 2018, Shift 1 · Q72
If x=√(2^cosec^-1 t) and y=√(2^sec^-1 t)(| t | ≥ 1), then (d y)/(d x) is equal to:
If $\displaystyle x=\sqrt{2^{\operatorname{cosec}^{-1} \mathrm{t}}}$ and $\displaystyle y=\sqrt{2^{\sec ^{-1} \mathrm{t}}}(|\mathrm{t}| \geqslant 1)$, then $\displaystyle \frac{\mathrm{d} y}{\mathrm{~d} x}$ is equal to :
Official answer
(3)
$\displaystyle -\frac{y}{x}$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.