Mathematics · 2024
JEE Main · 27 January 2024, Shift 1 · Q5
^n-1 C_r=(k^2-8)^n C_r+1 if and only if:
$\displaystyle { }^{n-1} C_r=\left(k^2-8\right){ }^n C_{r+1}$ if and only if :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 2 \sqrt{2}<\mathrm{k} \leq 3$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.