Mathematics · 2019
JEE Main · 8 April 2019, Shift 1 · Q62
If α and β be the roots of the equation x^2-2 x+2=0, then the least value of n for which ((α)/(β))^n =1 is:
If $\displaystyle \alpha$ and $\displaystyle \beta$ be the roots of the equation $\displaystyle x^2-2 x+2=0$, then the least value of n for which $\displaystyle \left(\frac{\alpha}{\beta}\right)^{\mathrm{n}}=1$ is :
Official answer
(2)
$\displaystyle 4$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.