Mathematics · 2018
JEE Main · 15 April 2018, Shift 1 · Q88
If tan A and tan B are the roots of the quadratic equation, 3 x^2-10 x-25=0, then the value of 3 sin^2( A + B ) -10 sin ( A + B ) · cos ( A + B )-25…
If $\displaystyle \tan \mathrm{A}$ and $\displaystyle \tan \mathrm{B}$ are the roots of the quadratic equation, $\displaystyle 3 x^2-10 x-25=0$, then the value of $\displaystyle 3 \sin ^2(\mathrm{~A}+\mathrm{B})$
$\displaystyle -10 \sin (\mathrm{~A}+\mathrm{B}) \cdot \cos (\mathrm{A}+\mathrm{B})-25 \cos ^2(\mathrm{~A}+\mathrm{B})$ is :
Official answer
(3)
$\displaystyle -25$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.