Mathematics · 2019
JEE Main · 12 January 2019, Shift 2 · Q82
If an angle between the line, (x+1)/2=(y-2)/1=(z-3)/-2 and the plane, x-2 y- k z=3 is cos^-1((2 √ 2)/3), then a value of k is:
If an angle between the line, $\displaystyle \frac{x+1}{2}=\frac{y-2}{1}=\frac{z-3}{-2}$ and the plane, $\displaystyle x-2 y-\mathrm{k} z=3$ is $\displaystyle \cos ^{-1}\left(\frac{2 \sqrt{2}}{3}\right)$, then a value of k is :
Official answer
(1)
$\displaystyle \sqrt{\frac{5}{3}}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.