Mathematics · 2018
JEE Main · 16 April 2018, Shift 1 · Q88
If an angle A of a ABC satisfies 5 cos A +3=0, then the roots of the quadratic equation, 9 x^2+27 x+20=0 are:
If an angle A of a $\displaystyle \triangle \mathrm{ABC}$ satisfies $\displaystyle 5 \cos \mathrm{~A}+3=0$, then the roots of the quadratic equation, $\displaystyle 9 x^2+27 x+20=0$ are :
Official answer
(3)
$\displaystyle \sec \mathrm{A}, \tan \mathrm{A}$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.