Mathematics · 2013
JEE Main · 25 April 2013, Shift 1 · Q73
For 0 ≤ x ≤ (π)/2, the value of ∫_0^sin^2 x sin^-1(√ t ) dt +∫_0^cos^2 x cos^-1(√ t ) dt equals:
For $\displaystyle 0 \leq x \leq \frac{\pi}{2}$, the value of
$$\int_0^{\sin ^2 x} \sin ^{-1}(\sqrt{\mathrm{t}}) \mathrm{dt}+\int_0^{\cos ^2 x} \cos ^{-1}(\sqrt{\mathrm{t}}) \mathrm{dt}
$$
equals :
Official answer
(1)
$\displaystyle \frac{\pi}{4}$
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.