Mathematics · 2015
JEE Main · 10 April 2015, Shift 1 · Q75
For x>0, let f(x)=∫_1^x (log t)/(1+ t) dt. Then f(x)+f(1/x) is equal to:
For $\displaystyle x>0$, let $\displaystyle f(x)=\int_1^x \frac{\log \mathrm{t}}{1+\mathrm{t}} \mathrm{dt}$. Then $\displaystyle f(x)+f\left(\frac{1}{x}\right)$ is equal to :
Official answer
(2)
$\displaystyle \frac{1}{2}(\log x)^2$
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JEE Main 2015 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.