Mathematics · 2016
JEE Main · 9 April 2016, Shift 1 · Q67
For x ∈ R, x ≠-1, if (1+x)^2016+x(1+x)^2015+x^2(1+x)^2014 +… …+x^2016=Σ_i=0^2016 a_i x^i, then a_17 is equal to:
For $\displaystyle x \in \mathbf{R}, x \neq-1$, if
$$(1+x)^{2016}+x(1+x)^{2015}+x^2(1+x)^{2014}
$$
$\displaystyle +\ldots \ldots+x^{2016}=\sum_{i=0}^{2016} a_i x^i$, then $\displaystyle a_{17}$ is equal to :
Official answer
(1)
$\displaystyle \frac{2017!}{17!2000!}$
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JEE Main 2016 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.