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Mathematics · 2018

JEE Main 2018 · 2018-04-08 Offline · Q70

For each t ∈ R, let [ t ] be the greatest integer less than or equal to t. Then lim_x → 0+ x([1/x]+[2/x]+…..+[15/x])

For each $\displaystyle \mathrm{t} \in \mathbf{R}$, let $\displaystyle [\mathrm{t}]$ be the greatest integer less than or equal to t . Then $$\lim _{x \rightarrow 0+} x\left(\left[\frac{1}{x}\right]+\left[\frac{2}{x}\right]+\ldots . .+\left[\frac{15}{x}\right]\right) $$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.