Mathematics · 2018
JEE Main · 15 April 2018, Shift 2 · Q70
lim_x → 0 (x tan 2 x-2 x tan x)/((1- cos 2 x)^2) equals:
$\displaystyle \lim _{x \rightarrow 0} \frac{x \tan 2 x-2 x \tan x}{(1-\cos 2 x)^2}$ equals :
Official answer
(3)
$\displaystyle \frac{1}{2}$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.