Mathematics · 2024
JEE Main · 1 February 2024, Shift 2 · Q19
Consider 10 observations x_1, x_2, …, x_10 such that Σ_i=1^10(x_i-α)=2 and Σ_i=1^10(x_i-β)^2=40, where α, β are positive integers. Let the mean and…
Consider $\displaystyle 10$ observations $\displaystyle x_1, x_2, \ldots, x_{10}$ such that $\displaystyle \sum_{i=1}^{10}\left(x_i-\alpha\right)=2$ and $\displaystyle \sum_{i=1}^{10}\left(x_i-\beta\right)^2=40$, where $\displaystyle \alpha, \beta$ are positive integers. Let the mean and the variance of the observations be $\displaystyle \frac{6}{5}$ and $\displaystyle \frac{84}{25}$ respectively. Then $\displaystyle \frac{\beta}{\alpha}$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 2$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.