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Mathematics · 2013
JEE Main 2013 · 2013-04-07 Offline · Q30
ABCD is a trapezium such that AB and CD are parallel and BC ⊥ CD. If ∠ ADB =θ, BC = p and CD = q, then AB is equal to:
ABCD is a trapezium such that AB and CD are parallel and $\displaystyle \mathrm{BC} \perp \mathrm{CD}$. If $\displaystyle \angle \mathrm{ADB}=\theta$, $\displaystyle \mathrm{BC}=\mathrm{p}$ and $\displaystyle \mathrm{CD}=\mathrm{q}$, then AB is equal to :
Official answer
(2)
$\displaystyle \frac{\left(p^2+q^2\right) \sin \theta}{p \cos \theta+q \sin \theta}$
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.