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Mathematics · 2019
JEE Main · 10 January 2019, Shift 2 · Q89
With the usual notation, in Δ ABC, if ∠ A +∠ B =120^°, a =√ 3 +1 and b =√ 3 -1, then the ratio ∠ A: ∠ B, is:
With the usual notation, in $\displaystyle \Delta \mathrm{ABC}$, if $\displaystyle \angle \mathrm{A}+\angle \mathrm{B}=120^{\circ}, \quad \mathrm{a}=\sqrt{3}+1 \quad$ and $\displaystyle \mathrm{b}=\sqrt{3}-1$, then the ratio $\displaystyle \angle \mathrm{A}: \angle \mathrm{B}$, is :
Official answer
(4)
$\displaystyle 7$ : $\displaystyle 1$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.