Mathematics · 2021
JEE Main · 27 August 2021, Shift 1 · Q74
Let (sin A)/(sin B)=(sin (A-C))/(sin (C-B)), where A, B, C are angles of a triangle ABC. If the lengths of the sides opposite these angles are a, b,…
Let $\displaystyle \frac{\sin A}{\sin B}=\frac{\sin (A-C)}{\sin (C-B)}$, where A, B, C are angles of a triangle ABC. If the lengths of the sides opposite these angles are $\displaystyle \mathrm{a}, \mathrm{b}, \mathrm{c}$ respectively, then :
Official answer
(2)
$\displaystyle \mathrm{b}^2, \mathrm{c}^2, \mathrm{a}^2 \text { are in A.P. }$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.