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Mathematics · 2015
JEE Main · 10 April 2015, Shift 1 · Q88
In a ABC, a/b=2+√ 3 and ∠ C =60^°. Then the ordered pair (∠ A, ∠ B ) is equal to:
In a $\displaystyle \triangle \mathrm{ABC}, \frac{\mathrm{a}}{\mathrm{b}}=2+\sqrt{3}$ and $\displaystyle \angle \mathrm{C}=60^{\circ}$.
Then the ordered pair $\displaystyle (\angle \mathrm{A}, \angle \mathrm{B})$ is equal to :
Official answer
(2)
($\displaystyle 105$°, $\displaystyle 15$°)
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JEE Main 2015 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.