Mathematics · 2021
JEE Main · 31 August 2021, Shift 1 · Q82
A point z moves in the complex plane such that ((z-2)/(z+2))=(π)/4, then the minimum value of |z-9 √ 2 -2 i|^2 is equal to \ \ \ \.
A point $\displaystyle z$ moves in the complex plane such that $\displaystyle \arg \left(\frac{z-2}{z+2}\right)=\frac{\pi}{4}$, then the minimum value of $\displaystyle |z-9 \sqrt{2}-2 i|^2$ is equal to \_\_\_\_.
Official answer
98
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.