Chemistry · 2021
JEE Main · 16 March 2021, Shift 2 · Q51
When 35 mL of 0.15 M lead nitrate solution is mixed with 20 mL of 0.12 M chromic sulphate solution, \ \ \ \ × 10^-5 moles of lead sulphate…
When $\displaystyle 35$ mL of $\displaystyle 0.15$ M lead nitrate solution is mixed with $\displaystyle 20$ mL of $\displaystyle 0.12$ M chromic sulphate solution, \_\_\_\_$\displaystyle \times 10^{-5}$ moles of lead sulphate precipitate out. (Round off to the Nearest Integer).
Official answer
525
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.