Chemistry · 2021
JEE Main · 26 February 2021, Shift 2 · Q51
The NaNO_3 weighed out to make 50 mL of an aqueous solution containing 70.0 mg Na^+ per mL is \ \ \ \ g. (Rounded off to the nearest integer) [Given:…
The $\displaystyle \mathrm{NaNO}_3$ weighed out to make $\displaystyle 50$ mL of an aqueous solution containing $\displaystyle 70.0 \mathrm{mg} \mathrm{Na}^{+}$ per mL is \_\_\_\_ g. (Rounded off to the nearest integer)
[Given : Atomic weight in $\displaystyle \mathrm{g} \mathrm{mol}^{-1}$ - $\displaystyle \mathrm{Na}: 23 ; \mathrm{N}: 14 ; \mathrm{O}: 16$ ]
Official answer
13
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