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Chemistry · 2021

JEE Main · 26 February 2021, Shift 2 · Q55

When 12.2 g of benzoic acid is dissolved in 100 g of water, the freezing point of solution was found to be -0.93^° C ( K_f( H_2 O )=1.86 K kg…

When $\displaystyle 12.2$ g of benzoic acid is dissolved in $\displaystyle 100$ g of water, the freezing point of solution was found to be $\displaystyle -0.93^{\circ} \mathrm{C}\left(\mathrm{K}_f\left(\mathrm{H}_2 \mathrm{O}\right)=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right)$. The number (n) of benzoic acid molecules associated (assuming $\displaystyle 100 \%$ association) is \_\_\_\_.
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.