224 mL of SO_2( g ) at 298 K and 1 atm is passed through 100 mL of 0.1 M NaOH solution. The non-volatile solute produced is dissolved in 36 g of…

$\displaystyle 224$ mL of $\displaystyle \mathrm{SO}_{2(\mathrm{~g})}$ at $\displaystyle 298$ K and $\displaystyle 1$ atm is passed through $\displaystyle 100$ mL of $\displaystyle 0.1$ M NaOH solution. The non-volatile solute produced is dissolved in $\displaystyle 36$ g of water. The lowering of vapour pressure of solution (assuming the solution is dilute) $\displaystyle \left(\mathrm{P}_{\left(\mathrm{H}_2 \mathrm{O}\right)}^{\circ}=24 \mathrm{~mm}\right.$ of Hg$\displaystyle )$ is $\displaystyle x \times 10^{-2} \mathrm{~mm}$ of Hg, the value of $\displaystyle x$ is \_\_\_\_. (Integer answer)