Chemistry · 2021
JEE Main · 27 August 2021, Shift 2 · Q58
The resistance of a conductivity cell with cell constant 1.14 cm^-1, containing 0.001 M KCl at 298 K is 1500 Ω. The molar conductivity of 0.001 M KCl…
The resistance of a conductivity cell with cell constant $\displaystyle 1.14 \mathrm{~cm}^{-1}$, containing $\displaystyle 0.001$ M KCl at $\displaystyle 298$ K is $\displaystyle 1500 \Omega$. The molar conductivity of $\displaystyle 0.001$ M KCl solution at $\displaystyle 298$ K in $\displaystyle \mathrm{S} \mathrm{cm}^2 \mathrm{~mol}^{-1}$ is \_\_\_\_. (Integer answer)
Official answer
760
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.