Offline paper
Chemistry · 2013
JEE Main 2013 · 2013-04-07 Offline · Q81
The rate of a reaction doubles when its temperature changes from 300 K to 310 K. Activation energy of such a reaction will be: ( R =8.314 JK^-1…
The rate of a reaction doubles when its temperature changes from $\displaystyle 300$ K to $\displaystyle 310$ K . Activation energy of such a reaction will be :
$\displaystyle \left(\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right.$ and $\displaystyle \log 2=0.301$ )
Official answer
(2)
$\displaystyle 53.6 \mathrm{~kJ} \mathrm{~mol}^{-1}$
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