Chemistry · 2016
JEE Main · 9 April 2016, Shift 1 · Q39
The reaction of ozone with oxygen atoms in the presence of chlorine atoms can occur by a two step process shown below: O_3( g )+ Cl^ ( g ) → O_2( g…
The reaction of ozone with oxygen atoms in the presence of chlorine atoms can occur by a two step process shown below :
$$\begin{gather*}
\mathrm{O}_3(\mathrm{~g})+\mathrm{Cl}^{\bullet}(\mathrm{g}) \rightarrow \mathrm{O}_2(\mathrm{~g})+\mathrm{ClO}^{\bullet}(\mathrm{g})-(\mathrm{i}) \\
\mathrm{k}_{\mathrm{i}}=5.2 \times 10^9 \mathrm{~L} \mathrm{~mol}^{-1} \mathrm{~s}^{-1} \\
\mathrm{ClO}^{\bullet}(\mathrm{g})+\mathrm{O}^{\bullet}(\mathrm{g}) \rightarrow \mathrm{O}_2(\mathrm{~g})+\mathrm{Cl}^{\bullet}(\mathrm{g})-(\mathrm{ii})\\
\mathrm{k}_{\mathrm{ii}}=2.6 \times 10^{10} \mathrm{~L} \mathrm{~mol}^{-1} \mathrm{~s}^{-1}
\end{gather*}
$$
The closest rate constant for the overall reaction $\displaystyle \mathrm{O}_3(\mathrm{~g})+\mathrm{O}^{\bullet}(\mathrm{g}) \rightarrow 2 \mathrm{O}_2(\mathrm{~g})$ is :
Official answer
(1)
$\displaystyle 5.2 \times 10^9 \mathrm{~L} \mathrm{~mol}^{-1} \mathrm{~s}^{-1}$
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JEE Main 2016 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.