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Chemistry · 2015

JEE Main · 11 April 2015, Shift 1 · Q39

A +2 B → C, the rate equation for this reaction is given as Rate = k [ A ][ B ]. If the concentration of A is kept the same but that of B is doubled…

$\displaystyle \mathrm{A}+2 \mathrm{~B} \rightarrow \mathrm{C}$, the rate equation for this reaction is given as $$\text { Rate }=\mathrm{k}[\mathrm{~A}][\mathrm{B}] . $$If the concentration of A is kept the same but that of B is doubled what will happen to the rate itself ?
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JEE Main 2015 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.