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Chemistry · 2021

JEE Main · 3 August 2021, Shift 2 · Q56

The potential of a cell containing two hydrogen electrodes, one in contact with 10^-8 M H^+ concentration and the other in contact with 0.025 M H^+…

The potential of a cell containing two hydrogen electrodes, one in contact with $\displaystyle 10^{-8} \mathrm{M} \mathrm{H}^{+}$concentration and the other in contact with $\displaystyle 0.025 \mathrm{M} \mathrm{H}^{+}$concentration is $\displaystyle x \times 10^{-4} \mathrm{~V}$. The value of $\displaystyle x$ is \_\_\_\_. (Nearest integer) [Given : $\displaystyle \frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059$ and $\displaystyle \log _{10} 2=0.30$ ]
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.