Chemistry · 2026
JEE Main · 28 January 2026, Shift 2 · Q53
The plot of log_10 K vs 1/T gives a straight line. The intercept and slope respectively are (where K is equilibrium constant).
The plot of $\displaystyle \log _{10} \mathrm{~K}$ vs $\displaystyle \frac{1}{\mathrm{~T}}$ gives a straight line. The intercept and slope respectively are (where K is equilibrium constant).
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \frac{\Delta \mathrm{S}^{\circ}}{2 \cdot 303 \mathrm{R}},-\frac{\Delta \mathrm{H}^{\circ}}{2 \cdot 303 \mathrm{R}}$
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.