Chemistry · 2021
JEE Main · 17 March 2021, Shift 1 · Q55
The oxygen dissolved in water exerts a partial pressure of 20 kPa in the vapour above water. The molar solubility of oxygen in water is \ \ \ \ ×…
The oxygen dissolved in water exerts a partial pressure of $\displaystyle 20$ kPa in the vapour above water. The molar solubility of oxygen in water is \_\_\_\_$\displaystyle \times 10^{-5} \mathrm{~mol} \mathrm{dm}^{-3}$.
(Round off to the Nearest Integer).
[Given :
$$\begin{aligned}
& \text { Henry's law constant }=\mathrm{K}_{\mathrm{H}}=8.0 \times 10^4 \mathrm{kPa} \text { for } \mathrm{O}_2 . \\
& \text { Density of water with dissolved oxygen } \left.=1.0 \mathrm{~kg} \mathrm{dm}^{-3}\right]
\end{aligned}
$$
Official answer
25
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