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Chemistry · 2021

JEE Main · 17 March 2021, Shift 1 · Q51

The mole fraction of a solute in a 100 molal aqueous solution is \ \ \ \ × 10^-2. (Round off to the Nearest Integer). [Given: Atomic masses: H: 1.0…

The mole fraction of a solute in a $\displaystyle 100$ molal aqueous solution is \_\_\_\_ $\displaystyle \times 10^{-2}$. (Round off to the Nearest Integer). [Given : Atomic masses : H : $\displaystyle 1.0$ u, O : $\displaystyle 16.0$ u]
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.