The number of N atoms in 681 g of C_7 H_5 N_3 O_6 is x × 10^21. The value of x is \ \ \ \. ( N_A =6.02 × 10^23 mol^-1) (Nearest Integer)

The number of N atoms in $\displaystyle 681$ g of $\displaystyle \mathrm{C}_7 \mathrm{H}_5 \mathrm{~N}_3 \mathrm{O}_6$ is $\displaystyle x \times 10^{21}$. The value of $\displaystyle x$ is \_\_\_\_. $\displaystyle \left(\mathrm{N}_{\mathrm{A}}=6.02 \times 10^{23} \mathrm{~mol}^{-1}\right)$ (Nearest Integer)