1 L aqueous solution of H_2 SO_4 contains 0.02 m mol H_2 SO_4. 50 % of this solution is diluted with deionized water to give 1 L solution (A). In…

$\displaystyle 1$ L aqueous solution of $\displaystyle \mathrm{H}_2 \mathrm{SO}_4$ contains $\displaystyle 0.02 \mathrm{~m} \mathrm{~mol} \mathrm{H}_2 \mathrm{SO}_4$. $\displaystyle 50 \%$ of this solution is diluted with deionized water to give $\displaystyle 1$ L solution (A). In solution (A), $\displaystyle 0.01$ m mol of $\displaystyle \mathrm{H}_2 \mathrm{SO}_4$ are added. Total m mols of $\displaystyle \mathrm{H}_2 \mathrm{SO}_4$ in the final solution is \_\_\_\_ $\displaystyle \times 10^3 \mathrm{~m}$ mols.