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Chemistry · 2023

JEE Main · 1 February 2023, Shift 2 · Q51

The molality of a 10 %( v / v ) solution of di-bromine solution in CCl_4 (carbon tetrachloride) is ' x '. x= ____ × 10^-2 M. (Nearest integer)…

The molality of a $\displaystyle 10 \%(\mathrm{v} / \mathrm{v})$ solution of di-bromine solution in $\displaystyle \mathrm{CCl}_4$ (carbon tetrachloride) is ' $\displaystyle x$ '. $\displaystyle x=$ $\displaystyle \_\_\_\_ \times 10^{-2} \mathrm{M}$. (Nearest integer) [Given : molar mass of $\displaystyle \mathrm{Br}_2=160 \mathrm{~g} \mathrm{~mol}^{-1}$ $$\begin{aligned} & \text { atomic mass of } \mathrm{C}=12 \mathrm{~g} \mathrm{~mol}^{-1} \\ & \text { atomic mass of } \mathrm{Cl}=35.5 \mathrm{~g} \mathrm{~mol}^{-1} \\ & \text { density of dibromine }=3.2 \mathrm{~g} \mathrm{~cm}^{-3} \\ & \text { density of } \mathrm{CCl}_4=1.6 \mathrm{~g} \mathrm{~cm}^{-3} \text { ] } \end{aligned} $$
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JEE Main 2023 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.