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Chemistry · 2025

JEE Main · 4 April 2025, Shift 1 · Q55

X Y is the membrane/partition between two chambers 1 and 2 containing sugar solutions of concentration c_1 and c_2( c_1> c_2) mol L^-1. For the…

$\displaystyle X Y$ is the membrane/partition between two chambers $\displaystyle 1$ and $\displaystyle 2$ containing sugar solutions of concentration $\displaystyle \mathrm{c}_1$ and $\displaystyle \mathrm{c}_2\left(\mathrm{c}_1>\mathrm{c}_2\right) \mathrm{mol} \mathrm{L}^{-1}$. For the reverse osmosis to take place identify the correct condition. (Here $\displaystyle \mathrm{p}_1$ and $\displaystyle \mathrm{p}_2$ are pressures applied on chamber $\displaystyle 1$ and $\displaystyle 2$). Figure: JEE Main Chemistry 2025, Solutions A. Membrane/Partition : Cellophane, $\displaystyle \mathrm{p}_1>\pi$ B. Membrane/Partition : Porous, $\displaystyle \mathrm{p}_2>\pi$ C. Membrane/Partition : Parchment paper, $\displaystyle \mathrm{p}_1>\pi$ D. Membrane/Partition : Cellophane, $\displaystyle \mathrm{p}_2>\pi$ Choose the correct answer from the option given below:
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JEE Main 2025 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.