Chemistry · 2022
JEE Main · 24 June 2022, Shift 2 · Q62
The energy of one mole of photons of radiation of wavelength 300 nm is (Given: h =6.63 × 10^-34 J s, N_A =6.02 × 10^23 mol^-1, c =3 × 10^8 m s^-1 )
The energy of one mole of photons of radiation of wavelength $\displaystyle 300$ nm is (Given : $\displaystyle \mathrm{h}=6.63 \times 10^{-34} \mathrm{~J} \mathrm{~s}, \mathrm{~N}_{\mathrm{A}}=6.02 \times 10^{23} \mathrm{~mol}^{-1,} \mathrm{c}=3 \times 10^8 \mathrm{~m} \mathrm{~s}^{-1}$ )
Official answer
(3)
$\displaystyle 399 \mathrm{~kJ} \mathrm{~mol}^{-1}$
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JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.