SolveIt is under development
SolveItJEE Main
Question 115 / 154 · latest first
Chemistry · 2022

JEE Main · 24 June 2022, Shift 2 · Q62

The energy of one mole of photons of radiation of wavelength 300 nm is (Given: h =6.63 × 10^-34 J s, N_A =6.02 × 10^23 mol^-1, c =3 × 10^8 m s^-1 )

The energy of one mole of photons of radiation of wavelength $\displaystyle 300$ nm is (Given : $\displaystyle \mathrm{h}=6.63 \times 10^{-34} \mathrm{~J} \mathrm{~s}, \mathrm{~N}_{\mathrm{A}}=6.02 \times 10^{23} \mathrm{~mol}^{-1,} \mathrm{c}=3 \times 10^8 \mathrm{~m} \mathrm{~s}^{-1}$ )
ShareWhatsAppTelegram

More from Atomic Structure

JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.