Chemistry · 2024
JEE Main · 9 April 2024, Shift 2 · Q81
Based on Heisenberg's uncertainty principle, the uncertainty in the velocity of the electron to be found within an atomic nucleus of diameter 10^-15…
Based on Heisenberg's uncertainty principle, the uncertainty in the velocity of the electron to be found within an atomic nucleus of diameter $\displaystyle 10^{-15} \mathrm{~m}$ is $\displaystyle \_\_\_\_$× $\displaystyle 10^9 \mathrm{~ms}^{-1}$ (nearest integer)
[Given : mass of electron $\displaystyle =9.1 \times 10^{-31} \mathrm{~kg}$, Plank's constant $\displaystyle (h)=6.626 \times 10^{-34} \mathrm{Js}$ ] (Value of $\displaystyle \pi=3.14$ )
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From NTA’s final answer key for this paper.
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JEE Main 2024 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.