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Chemistry · 2024

JEE Main · 6 April 2024, Shift 2 · Q81

For hydrogen atom, energy of an electron in first excited state is -3.4 eV, K.E. of the same electron of hydrogen atom is x eV. Value of x is ____ ×…

For hydrogen atom, energy of an electron in first excited state is $\displaystyle -3.4 \mathrm{eV}, \mathrm{K.E.}$ of the same electron of hydrogen atom is $\displaystyle x \mathrm{eV}$. Value of $\displaystyle x$ is $\displaystyle \_\_\_\_$ $\displaystyle \times 10^{-1} \mathrm{eV}$. (Nearest integer)
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JEE Main 2024 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.