Chemistry · 2024
JEE Main · 9 April 2024, Shift 1 · Q61
Compare the energies of following sets of quantum numbers for multielectron system. (A) n =4, l =1 (B) n =4, l =2 (C) n =3, l =1 (D) n =3, l =2 (E) n…
Compare the energies of following sets of quantum numbers for multielectron system.
(A)
$\displaystyle \mathrm{n}=4, \mathrm{l}=1$
(B)
$\displaystyle \mathrm{n}=4, \mathrm{l}=2$
(C)
$\displaystyle \mathrm{n}=3, \mathrm{l}=1$
(D)
$\displaystyle \mathrm{n}=3, \mathrm{l}=2$
(E)
$\displaystyle \mathrm{n}=4, \mathrm{l}=0$
Choose the correct answer from the options given below :
Official answer
From NTA’s final answer key for this paper.
(2)
(C) < (E) < (D) < (A) < (B)
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JEE Main 2024 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.