Consider the following pairs of electrons (A) (a) n =3, l =1, m_l =1, m_s =+1/2 (b) n =3, l =2, m_l =1, m_s =+1/2 (B) (a) n =3, l =2, m_l =-2, m_s =-1/2 (b) n =3, l =2, m_l =-1, m_s =-1/2 (C) (a) n =4, l =2, m_l =2, m_s =+1/2 (b) n =3, l =2, m_l =2, m_s =+1/2 The pairs of electrons present in degenerate orbitals is/are:

Consider the following pairs of electrons n=3, l=1, m_l=1, m_s=+1/2 n=3, l=2, m_l=1,…

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Chemistry · 2022

JEE Main · 24 June 2022, Shift 1 · Q62

Consider the following pairs of electrons

(A)(a)

$\displaystyle \mathrm{n}=3, \mathrm{l}=1, \mathrm{~m}_{\mathrm{l}}=1, \mathrm{~m}_{\mathrm{s}}=+\frac{1}{2}$

(b)

$\displaystyle \mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_{\mathrm{l}}=1, \mathrm{~m}_{\mathrm{s}}=+\frac{1}{2}$

(B)(a)

$\displaystyle \mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_{\mathrm{l}}=-2, \mathrm{~m}_{\mathrm{s}}=-\frac{1}{2}$

(b)

$\displaystyle \mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_{\mathrm{l}}=-1, \mathrm{~m}_{\mathrm{s}}=-\frac{1}{2}$

(C)(a)

$\displaystyle \mathrm{n}=4, \mathrm{l}=2, \mathrm{~m}_{\mathrm{l}}=2, \mathrm{~m}_{\mathrm{s}}=+\frac{1}{2}$

(b)

$\displaystyle \mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_{\mathrm{l}}=2, \mathrm{~m}_{\mathrm{s}}=+\frac{1}{2}$

The pairs of electrons present in degenerate orbitals is/are :

JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.