Chemistry · 2014
JEE Main · 12 April 2014, Shift 1 · Q34
The amount of BaSO_4 formed upon mixing 100 mL of 20.8 % BaCl_2 solution with 50 mL of 9.8 % H_2 SO_4 solution will be: ( Ba =137, Cl =35.5, S =32, H…
The amount of $\displaystyle \mathrm{BaSO}_4$ formed upon mixing $\displaystyle 100$ mL of $\displaystyle 20.8 \% \mathrm{BaCl}_2$ solution with $\displaystyle 50$ mL of $\displaystyle 9.8 \% \mathrm{H}_2 \mathrm{SO}_4$ solution will be : $\displaystyle (\mathrm{Ba}=137, \mathrm{Cl}=35.5, \mathrm{~S}=32, \mathrm{H}=1$ and $\displaystyle \mathrm{O}=16$ )
Official answer
(2)
11.$\displaystyle 65$ g
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